A cylinder of mass 10 kg and radius 15 cm is rolling perfectly on a plane of inclination 30°. The coefficient of static friction μs = 0.25.

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asked Mar 8, 2018 in Physics by paayal (26,720 points) 4 6 11

A cylinder of mass 10 kg and radius 15 cm is rolling perfectly on a plane of inclination 30°. The coefficient of static friction μs = 0.25.

How much is the force of friction acting on the cylinder?
What is the work done against friction during rolling?
If the inclination θ of the plane is increased, at what value of θ does the cylinder begin to skid, and not roll perfectly?

1 Answer

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answered Mar 8, 2018 by Vikash Kumar (144,729 points) 8 11 21
 
Best answer

The various forces acting on the cylinder are shown in the following figure:

The acceleration of the cylinder is given as:

Using Newton’s second law of motion, we can write net force as:

During rolling, the instantaneous point of contact with the plane comes to rest. Hence, the work done against frictional force is zero.
For rolling without skid, we have the relation:

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