A solid cylinder rolling up an inclination is shown in the following figure.
Using the law of conservation of energy, we can write:
Hence, the cylinder will travel 3.82 m up the inclined plane.
Forradius of gyration K, the velocity of the cylinder at the instance when it rolls back to the bottom is given by the relation:
The time taken to return to the bottom is:
Therefore, the total time taken by the cylinder to return to the bottom is (2 X 0.764) =1.53s.
