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Find the value of sin70°/cos20° + tan25° + sec^2 75° - cot^2 15°- 3tan5°tan7°tan83°tan85°

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asked Mar 12, 2018 in Mathematics by Golu (37,045 points) ● 19 ● 146 ● 417
edited Mar 12, 2018 by Golu

Without using tables, find the value of

sin70°/cos20° + tan25° + sec275° - cot215°- 3tan5°tan7°tan83°tan85°

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answered Mar 12, 2018 by faiz (82,347 points) ● 6 ● 6 ● 11
edited Mar 12, 2018 by faiz
 
Best answer

=1+1+1-3 x 1 [tan​θcotθ=1, sec2θ​-tan2θ​=1]

=3-3=0

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