If cosec θ – sin θ = l and sec θ – cos θ = m, prove that l^2 m^2 (l^2 + m^2 + 3) = 1.

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answered Mar 15, 2018 by mdsamim (213,225 points)
selected Mar 20, 2018 by faiz

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If cosec θ – sin θ = l and sec θ – cos θ = m, prove that l^2 m^2 (l^2 + m^2 + 3) = 1.

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