Find the probability of getting 53 Fridays in a leap year,

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asked Mar 19, 2018 in Mathematics by shabnam praween (19,050 points) 5 6 8
Find the probability of getting 53 Fridays in a leap year,

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answered Mar 19, 2018 by santoshjha (25,550 points) 4 5 6
selected Mar 27, 2018 by Vikash Kumar
 
Best answer

Leap year = 366 days = (52 × 7 + 2) days = 52 weeks and 2 days.

Thus, a leap year always has 52 Fridays.
The remaining 2 days can be:
(i) Sunday and Monday 

(ii) Monday and Tuesday
(iii) Tuesday and Wednesday 

(iv) Wednesday and Thursday
(v) Thursday and Friday

 (vi) Friday and Saturday
(vii) Saturday and Sunday

Out of these 7 cases, we have Fridays in two cases

P(53 Fridays)=2/7

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