
Given that, λ= (400 nm to 700 nm), d = 0.5 mm = 0.5x10–3 m,
D = 50 cm = 0.5 m and on the screen yn = 1 mm = 1x10–3 m
a) We know that for zero intensity (dark fringe)



So, the light waves of wavelengths 400 nm and 667 nm will be absent from the out coming light.
b) For strong intensity (bright fringes) at the hole

So, the only wavelength which will have strong intensity is 500 nm.