In a Young's double slit experiment, the separation between the slits = 2.0 mm, the wavelength of the light = 600 nm

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asked Mar 31, 2018 in Physics by Nisa (2,540 points) 1 3

In a Young's double slit experiment, the separation between the slits = 2.0 mm, the wavelength of the light = 600 nm and the distance of the screen from the slits = 2.0 m. If the intensity at the centre of the central maximum is 0.20 W/m2, what will be the intensity at a point 0.5 cm away from this centre along the width of the fringes ?

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answered Mar 31, 2018 by rubby (7,550 points) 1 3 5
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

Given that, d = 2 mm = 2x10–3 m, λ= 600 nm = 6 x10–7 m, Imax = 0.20 W/m2, D = 2m

For the point, y = 0.5 cm

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