A thin spherical shell lying on a rough horizontal surface is hit by a cue in such a way that the line of action passes through the centre of the

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asked Mar 31, 2018 in Physics by anukriti (13,536 points) 5 10 19

A thin spherical shell lying on a rough horizontal surface is hit by a cue in such a way that the line of action passes through the centre of the shell. As a result, the shell starts moving with a linear speed v without any initial angular velocity. Find the linear speed of the shell after it starts pure rolling on the surface.

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answered Mar 31, 2018 by faiz (82,347 points) 6 6 11
selected Mar 31, 2018 by anukriti
 
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The shell will move with a velocity nearly equal to v due to this motion a frictional force well act in the background direction, for which after some time the shell attains a pure rolling. If we consider moment about A, then it will be zero. Therefore, Net angular momentum about A before pure rolling = net angular momentum after pure rolling. Now, angular momentum before pure rolling about A = M (V × R) and angular momentum after pure rolling:-

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