In a Young's double slit experiment λ= 500 nm, d = 1.0 mm and D = 1.0 m.

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asked Mar 31, 2018 in Physics by Nisa (2,540 points) 1 3

In a Young's double slit experiment λ= 500 nm, d = 1.0 mm and D = 1.0 m. Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

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answered Mar 31, 2018 by rubby (7,550 points) 1 3 5
selected Apr 1, 2018 by Vikash Kumar
 
Best answer

Given that, D = 1 m, d = 1 mm = 10–3 m, λ= 500 nm = 5 x10–7 m

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