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How to prove sec^4A-sec^2A=tan^4A+tan^2A

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+2 votes
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asked Jun 30, 2017 in Mathematics by Siddarth todi (75 points) ● 1 ● 5

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+1 vote
answered Jun 30, 2017 by sarthaks (25,122 points) ● 9 ● 25 ● 41
 
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Solution: 

Explanation: Use one of the Pythagorean identity namely,

sec2A=1+tan2A

LHS = sec4A−sec2A
=(sec2A)2−sec2A
=(1+tan2A)2−(1+tan2A)
=1+2tan2A+tan4A−1−tan2A

=tan4A+tan2A

= RHS

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