Find (a) the total number and (b) the total mass of neutrons in 7 mg of ^14C. (Assume that mass of a neutron = 1.675 × 10^–27 kg).

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asked Aug 7, 2017 in Chemistry by sforrest072 (157,439 points) 61 411 949

Find (a) the total number and (b) the total mass of neutrons in 7 mg of 14C.
(Assume that mass of a neutron = 1.675 × 10–27 kg).

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answered Aug 7, 2017 by faiz (82,347 points) 6 6 11
selected Aug 7, 2017 by sforrest072
 
Best answer

(a) Number of atoms of 14C in 1 mole= 6.023 × 1023
Since 1 atom of 14C contains (14 – 6) i.e., 8 neutrons, the number of neutrons in 14 g of 14C is (6.023 × 1023) ×8. Or, 14 g of 14C contains (6.022 × 1023 × 8) neutrons.
Number of neutrons in 7 mg

6.022*1023*8*7 mg/1400 mg

= 2.4092 × 1021
(b) Mass of one neutron = 1.67493 × 10–27 kg
Mass of total neutrons in 7 g of 14C
= (2.4092 × 1021) (1.67493 × 10–27 kg)
= 4.0352 × 10–6 kg
 

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