Question

The equilibrium constant for a reaction is 10. What will be the value of ∆G^θ? R = 8.314 JK– 1 mol^–1 , T = 300 K. 

Answer 1

From the expression, 

∆G^θ = –2.303 RT logK_eq 

∆G^θ for the reaction, = (2.303) (8.314 JK^{–1 mol–1} ) (300 K) log₁₀ 

= –5744.14 Jmo^l–1 

= –5.744 kJ mol^–1