Question

Calculate the pH of the following solutions: 

(a) 2_g of TlOH dissolved in water to give 2 litre of solution.

(b) 0.3_g of Ca(OH)₂ dissolved in water to give 500 mL of solution. 

(c) 0.3_g of NaOH dissolved in water to give 200 mL of solution. 

(d) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.

Answer 1

(a) For 2_g of TlOH dissolved in water to give 2 L of solution: 

(b) For 0.3 _g of Ca(OH)₂ dissolved in water to give 500 mL of solution: 

(c) For 0.3 _g of NaOH dissolved in water to give 200 mL of solution: 

(d) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution: 

13.6 × 1 mL = M₂ × 1000 mL 

(Before dilution) (After dilution) 

13.6 × 10^–3 = M₂ × 1L M₂ 

= 1.36 × 10–2 [H⁺] = 1.36 × 10^–2 pH = – log (1.36 × 10^–2 ) 

= (– 0.1335 + 2) = 1.866 =1.87