Percentage of carbon in organic compound = 69 %
That is, 100 g of organic compound contains 69 g of carbon.
0.2 g of organic compound will contain =(69X0.2)100=0.138G OF c
Molecular mass of carbon dioxide, CO2 = 44 g
That is, 12 g of carbon is contained in 44 g of CO2.
Therefore, 0.138 g of carbon will be contained in (44X0.138)/12 = 0.506 g of CO2
Thus, 0.506 g of CO2 will be produced on complete combustion of 0.2 g of organic compound. Percentage of hydrogen in organic compound is 4.8. i.e., 100 g of organic compound contains 4.8 g of hydrogen.
Therefore, 0.2 g of organic compound will contain (4.8x0.2/100)=0.0096g of H
It is known that molecular mass of water (H2O) is 18 g. Thus, 2 g of hydrogen is contained in 18 g of water.
0.0096 g of hydrogen will be contained in (18X0.00096/2)=0.0864g of water
Thus, 0.0864 g of water will be produced on complete combustion of 0.2 g of the organic compound.