(a) Given:
Mass of the missile, m = 75 kg and Speed, v = 60 m/s
Therefore, K.E. = 1/ 2 mv2 = 1 /2 × 75 × 60 × 60 = 13500 J
(b) Given,
Mass of the missile, m = 75 kg
Acceleration due to gravity, g = 10 m/s2 and Height, h = 850 m
Therefore, P.E. = m × g × h = 75 × 10 × 850 = 637500 J
(c) Total mechanical energy of the missile = K.E. + P.E.
= 135000 + 637500 = 7.7 × 105J
(d) K.E. at the ground = 7.7 × 105J
K.E. = 1 /2 mv2 , Therefore, v2 = 2 K.E. / m

Velocity with which missile strikes the ground =143.2 m/s