The slope of the tangent to the curve x= t^2+3t-8, y=2t^2-2t-5 at the point (2, −1) is

0 votes
17 views
asked Jan 23, 2018 in Mathematics by sforrest072 (157,439 points) 61 411 949

The slope of the tangent to the curve x= t2+3t-8, y=2t2-2t-5 at the point (2, −1) is

(A)  22/7   (B)   6/7   (C) 7/6  (D)  -6/7

1 Answer

0 votes
answered Jan 23, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 23, 2018 by sforrest072
 
Best answer

The given point is (2, −1).

At x = 2, we have:

The common value of t is 2.
Hence, the slope of the tangent to the given curve at point (2, −1) is

The correct answer is B.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...