Find the probability of getting 53 Sundays in a non-leap year?

+1 vote
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asked Mar 4, 2018 in Mathematics by Anuja (1,123 points) 1 3 8
Find the probability of getting  53 Sundays in a non-leap year?

1 Answer

+2 votes
answered Mar 4, 2018 by Annu Priya (18,055 points) 24 45 82
selected Mar 5, 2018 by Anuja
 
Best answer

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1day extra.

In a non-leap year there will be 52 Sundays and 1day will be left.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 Sundays = 1 / 7.

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